2.5x^2-12x+8=0

Solution for 2.5x^2-12x+8=0 equation:

2.5x^2-12x+8=0

a = 2.5; b = -12; c = +8;
Δ = b2-4ac
Δ = -122-4·2.5·8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8}{2*2.5}=\frac{4}{5}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8}{2*2.5}=\frac{20}{5}
=4
$